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Find the Area of the Surface of Revolution r(u,v)=11sinucosvi+11uj+11sinusinvk\mathbf { r } ( u , v ) = 11 \sin u \cos v \mathbf { i } + 11 u \mathbf { j } + 11 \sin u \sin v \mathbf { k }

Question 23

Multiple Choice

Find the area of the surface of revolution r(u,v) =11sinucosvi+11uj+11sinusinvk\mathbf { r } ( u , v ) = 11 \sin u \cos v \mathbf { i } + 11 u \mathbf { j } + 11 \sin u \sin v \mathbf { k } , where 0uπ0 \leq u \leq \pi and 0v2π0 \leq v \leq 2 \pi .


A) 121π[2+ln21]121 \pi [ \sqrt { 2 } + \ln | \sqrt { 2 } - 1 | ]
B) 22π[2+ln2+1]22 \pi [ \sqrt { 2 } + \ln | \sqrt { 2 } + 1 | ]
C) 242π[2+ln212+1]242 \pi \left[ \sqrt { 2 } + \ln \left| \frac { \sqrt { 2 } - 1 } { \sqrt { 2 } + 1 } \right| \right]
D) π[2ln2+1]\pi [ \sqrt { 2 } - \ln | \sqrt { 2 } + 1 | ]
E) 242π[2+ln2+121]242 \pi \left[ \sqrt { 2 } + \ln \left| \frac { \sqrt { 2 } + 1 } { \sqrt { 2 } - 1 } \right| \right]

Correct Answer:

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