Find the Absolute Extreme Values of the Function on the Interval

Multiple Choice

Find the absolute extreme values of the function on the interval.
- $$F ( x ) = \sqrt [ 3 ] { x } , - 2 \leq x \leq 64$$

A) absolute maximum is 0 at $x = 0$ ; absolute minimum is 4 at $x = 64$
B) absolute maximum is 4 at $x = 64$ ; absolute minimum is $- 4$ at $x = - 64$
C) absolute maximum is 4 at $x = - 64$ ; absolute minimum is 0 at $x = 0$
D) absolute maximum is 4 at $x = 64$ ; absolute minimum is 0 at $x = 0$