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Find the Derivative of the Function y=x2+8x+3xy = \frac { x ^ { 2 } + 8 x + 3 } { \sqrt { x } }

Question 14

Multiple Choice

Find the derivative of the function.
- y=x2+8x+3xy = \frac { x ^ { 2 } + 8 x + 3 } { \sqrt { x } }


A) y=2x+82x3/2y ^ { \prime } = \frac { 2 x + 8 } { 2 x ^ { 3 / 2 } }
B) y=3x2+8x3xy ^ { \prime } = \frac { 3 x ^ { 2 } + 8 x - 3 } { x }
C) y=2x+8xy ^ { \prime } = \frac { 2 x + 8 } { x }
D) y=3x2+8x32x3/2y ^ { \prime } = \frac { 3 x ^ { 2 } + 8 x - 3 } { 2 x ^ { 3 / 2 } }

Correct Answer:

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