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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

Question 130

Multiple Choice

 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx0x22x+sinxx\lim _ { x \rightarrow 0 } \frac { x ^ { 2 } - 2 x + \sin x } { x }


A) does not exist
B) 0
C) 1- 1
D) 1

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