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Verify the Identity Shown Below tan⁡α+cot⁡βtan⁡αcot⁡β=tan⁡β+cot⁡α\frac { \tan \alpha + \cot \beta } { \tan \alpha \cot \beta } = \tan \beta + \cot \alpha

Question 19

Essay

Verify the identity shown below. tan⁡α+cot⁡βtan⁡αcot⁡β=tan⁡β+cot⁡α\frac { \tan \alpha + \cot \beta } { \tan \alpha \cot \beta } = \tan \beta + \cot \alpha

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\[\begin{aligned}
\frac { \tan \alpha + ...

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