Solve the System of Linear Equations A) B) C) D)

Multiple Choice

Solve the system of linear equations
$$\left\{ \begin{array} { l } 6 x _ { 1 } - 12 x _ { 2 } - 6 x _ { 3 } - 12 x _ { 4 } = 0 \\18 x _ { 1 } - 30 x _ { 2 } - 12 x _ { 3 } - 18 x _ { 4 } = - 3 \\12 x _ { 1 } - 30 x _ { 2 } - 12 x _ { 3 } - 30 x _ { 4 } = 2 \\- 6 x _ { 1 } + 24 x _ { 2 } + 24 x _ { 3 } + 66 x _ { 4 } = 0 \\{ \left[ \begin{array} { c c c c } - 24 & 7 & 1 & - 2 \\- 10 & 3 & 0 & - 1 \\- 29 & 7 & 3 & - 2 \\12 & - 3 & - 1 & 1\end{array} \right] }\end{array} \right.$$

A)
$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } - \frac { 19 } { 6 } \\- \frac { 3 } { 2 } \\- \frac { 5 } { 2 } \\\frac { 7 } { 6 }\end{array} \right]$
B)
$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } - \frac { 7 } { 6 } \\- \frac { 5 } { 6 } \\\frac { 3 } { 2 } \\- \frac { 3 } { 2 }\end{array} \right]$
C)
$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } - \frac { 3 } { 2 } \\- \frac { 19 } { 6 } \\0 \\\frac { 7 } { 6 }\end{array} \right]$
D)
$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } - \frac { 1 } { 2 } \\\frac { 1 } { 6 } \\0 \\\frac { 1 } { 3 }\end{array} \right]$
E)
$\left[ \begin{array} { l } x _ { 1 } \\x _ { 2 } \\x _ { 3 } \\x _ { 4 }\end{array} \right] = \left[ \begin{array} { c } 0 \\- \frac { 1 } { 6 } \\0 \\- \frac { 1 } { 3 }\end{array} \right]$