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Solve the System of Equations Algebraically {xy+289=04x25y340=0\left\{ \begin{array} { r } x y + 289 = 0 \\4 x - 25 y - 340 = 0\end{array} \right.

Question 56

Multiple Choice

Solve the system of equations algebraically.
{xy+289=04x25y340=0\left\{ \begin{array} { r } x y + 289 = 0 \\4 x - 25 y - 340 = 0\end{array} \right.


A) (85,175) \left( 85 , - \frac { 17 } { 5 } \right)
B) (85,175) ,(85,175) \left( - 85 , \frac { 17 } { 5 } \right) , \left( 85 , - \frac { 17 } { 5 } \right)
C) (852,345) \left( \frac { 85 } { 2 } , - \frac { 34 } { 5 } \right)
D) (852,345) ,(852,345) \left( - \frac { 85 } { 2 } , \frac { 34 } { 5 } \right) , \left( \frac { 85 } { 2 } , - \frac { 34 } { 5 } \right)
E) no solution

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