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An Object Moving Vertically Is at the Given Heights at the Specified

Question 102

Multiple Choice

An object moving vertically is at the given heights at the specified times. Find the position equation s=12at2+vot+sos = \frac { 1 } { 2 } a t ^ { 2 } + v _ { o } t + s _ { o } for the object.
At t=1t = 1 second, s=198s = 198 feet
At t=2t = 2 seconds, s=182s = 182 feet
At t=3t = 3 seconds, s=134s = 134 feet


A) s=32t2+32t+198s = - 32 t ^ { 2 } + 32 t + 198
B) s=16t2+32t182s = - 16 t ^ { 2 } + 32 t - 182
C) s=16t2+32t+182s = - 16 t ^ { 2 } + 32 t + 182
D) s=8t2+2t182s = - 8 t ^ { 2 } + 2 t - 182
E) s=16t232t+198\quad s = - 16 t ^ { 2 } - 32 t + 198

Correct Answer:

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