Solved

Find Pk+1P _ { k + 1 } For the Given PkP _ { k }

Question 17

Multiple Choice

Find Pk+1P _ { k + 1 } for the given PkP _ { k } .
Pk=4k(k+1) P _ { k } = \frac { 4 } { k ( k + 1 ) }


A) Pk+1=4k(k+1) +1 P _ { k + 1 } = \frac { 4 } { k ( k + 1 ) } + 1
B) Pk+1=4k(k+1) +4(k+1) (k+2) P _ { k + 1 } = \frac { 4 } { k ( k + 1 ) } + \frac { 4 } { ( k + 1 ) ( k + 2 ) }
C) Pk+1=4(k+1) (k+2) P _ { k + 1 } = \frac { 4 } { ( k + 1 ) ( k + 2 ) }
D) Pk+1=4k(k+2) P _ { k + 1 } = \frac { 4 } { k ( k + 2 ) }
E) Pk+1=16(k+1) (k+2) P _ { k + 1 } = \frac { 16 } { ( k + 1 ) ( k + 2 ) }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions