The Acceleration Due to Gravity at or near the Surface $1 / 6$

Short Answer

The acceleration due to gravity at or near the surface of the moon is approximately $1 / 6$ g. This is equal to:
a. $0.16 \mathrm {~m} / \mathrm { s } ^ { 2 }$

b. $64 \mathrm { in } / \mathrm { s } ^ { 2 }$

c. $0.16 { f t / s ^ { 2 } }$

d. $1.6 { ft } / \mathrm { s } ^ { 2 }$

e. None of the above