Gravitational Acceleration near the Earth's Surface Is $9.8 \mathrm {~m} / \mathrm { s } ^ { 2 }$

Short Answer

Gravitational acceleration near the Earth's surface is $9.8 \mathrm {~m} / \mathrm { s } ^ { 2 }$ or 32.2 $\mathrm { ft } / \mathrm { s } ^ { 2 }$ . Which is greater, an acceleration of $1 \mathrm {~m} / \mathrm { s } ^ { 2 } \text { or } 1 \mathrm { ft } / \mathrm { s } ^ { 2 }$ ? a. $1 \mathrm {~m} / \mathrm { s } ^ { 2 }$

b. $1 \mathrm { ft } / \mathrm { s } ^ { 2 }$