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Find an Equation of the Hyperbola Centered at the Origin (±4,0)( \pm 4,0 )

Question 19

Multiple Choice

Find an equation of the hyperbola centered at the origin that satisfies the given condition. Vertices: (±4,0) ( \pm 4,0 ) , asymptotes: y=±74xy = \pm \frac { 7 } { 4 } x


A) x216y249=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 49 } = 1
B) y249x216=1\frac { y ^ { 2 } } { 49 } - \frac { x ^ { 2 } } { 16 } = 1
C) y216x249=1\frac { y ^ { 2 } } { 16 } - \frac { x ^ { 2 } } { 49 } = 1
D) x249y216=1\frac { x ^ { 2 } } { 49 } - \frac { y ^ { 2 } } { 16 } = 1

Correct Answer:

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