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Solve the Inequality and Graph the Solution on the Real $\frac { x ^ { 2 } + x - 12 } { x } \geq 0$

Question 120

Multiple Choice

Solve the inequality and graph the solution on the real number line. $\frac { x ^ { 2 } + x - 12 } { x } \geq 0$

A) $[ - 4,0 ) \cap [ 3 , \infty )$
$Solve the inequality and graph the solution on the real number line. \frac { x ^ { 2 } + x - 12 } { x } \geq 0 A) [ - 4,0 ) \cap [ 3 , \infty ) B) [ 4,0 ) \cup [ 3 , \infty ) C) [ 4,0 ) \cup [ - 3 , \infty ) D) [ - 4,0 ) \cap [ - 3 , \infty ) E) [ - 4,0 ) \cup [ 3 , \infty )$

B) $[ 4,0 ) \cup [ 3 , \infty )$
$Solve the inequality and graph the solution on the real number line. \frac { x ^ { 2 } + x - 12 } { x } \geq 0 A) [ - 4,0 ) \cap [ 3 , \infty ) B) [ 4,0 ) \cup [ 3 , \infty ) C) [ 4,0 ) \cup [ - 3 , \infty ) D) [ - 4,0 ) \cap [ - 3 , \infty ) E) [ - 4,0 ) \cup [ 3 , \infty )$

C) $[ 4,0 ) \cup [ - 3 , \infty )$
$Solve the inequality and graph the solution on the real number line. \frac { x ^ { 2 } + x - 12 } { x } \geq 0 A) [ - 4,0 ) \cap [ 3 , \infty ) B) [ 4,0 ) \cup [ 3 , \infty ) C) [ 4,0 ) \cup [ - 3 , \infty ) D) [ - 4,0 ) \cap [ - 3 , \infty ) E) [ - 4,0 ) \cup [ 3 , \infty )$

D) $[ - 4,0 ) \cap [ - 3 , \infty )$
$Solve the inequality and graph the solution on the real number line. \frac { x ^ { 2 } + x - 12 } { x } \geq 0 A) [ - 4,0 ) \cap [ 3 , \infty ) B) [ 4,0 ) \cup [ 3 , \infty ) C) [ 4,0 ) \cup [ - 3 , \infty ) D) [ - 4,0 ) \cap [ - 3 , \infty ) E) [ - 4,0 ) \cup [ 3 , \infty )$

E) $[ - 4,0 ) \cup [ 3 , \infty )$
$Solve the inequality and graph the solution on the real number line. \frac { x ^ { 2 } + x - 12 } { x } \geq 0 A) [ - 4,0 ) \cap [ 3 , \infty ) B) [ 4,0 ) \cup [ 3 , \infty ) C) [ 4,0 ) \cup [ - 3 , \infty ) D) [ - 4,0 ) \cap [ - 3 , \infty ) E) [ - 4,0 ) \cup [ 3 , \infty )$

Solve the Inequality and Graph the Solution on the Real x2+x−12x≥0\frac { x ^ { 2 } + x - 12 } { x } \geq 0xx2+x−12​≥0

Multiple Choice

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Solve the Inequality and Graph the Solution on the Real $\frac { x ^ { 2 } + x - 12 } { x } \geq 0$

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