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Solve the Following Equation 4sin2x=12cos2x4 \sin ^ { 2 } x = 12 \cos ^ { 2 } x

Question 21

Multiple Choice

Solve the following equation.
4sin2x=12cos2x4 \sin ^ { 2 } x = 12 \cos ^ { 2 } x


A) 2π3+nπ,2π3+nπ\frac { 2 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi
B) π3+nπ,2π3+nπ\frac { \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi
C) π3+nπ,π3+nπ\frac { \pi } { 3 } + n \pi , \frac { \pi } { 3 } + n \pi
D) 4π3+nπ,2π3+nπ\frac { 4 \pi } { 3 } + n \pi , \frac { 2 \pi } { 3 } + n \pi
E) π2+nπ,2π5+nπ\frac { \pi } { 2 } + n \pi , \frac { 2 \pi } { 5 } + n \pi

Correct Answer:

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