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Calculate yy ^ { \prime } xy3+x3y=x+3yx y ^ { 3 } + x ^ { 3 } y = x + 3 y

Question 133

Multiple Choice

Calculate yy ^ { \prime } .
xy3+x3y=x+3yx y ^ { 3 } + x ^ { 3 } y = x + 3 y


A)

y=1y33x2y3xy2+x33y ^ { \prime } = \frac { 1 - y ^ { 3 } - 3 x ^ { 2 } y } { 3 x y ^ { 2 } + x ^ { 3 } - 3 }

B)

y=1y32x33xy2+x23y ^ { \prime } = \frac { 1 - y ^ { 3 } - 2 x ^ { 3 } } { 3 x y ^ { 2 } + x ^ { 2 } - 3 }

C)

yt=y43xy4xy3+x2y ^ { t } = \frac { - y ^ { 4 } - 3 x y } { 4 x y ^ { 3 } + x ^ { 2 } }

D)
yt=xy2+2x3x2y2(3x1) y ^ { t } = \frac { x y ^ { 2 } + 2 x - 3 } { x ^ { 2 } y ^ { 2 } ( 3 x - 1 ) }

E) none of these

Correct Answer:

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