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Find the Derivative of the Function g(x)=1x1t2+2dtg ( x ) = \int _ { 1 } ^ { x } \frac { 1 } { t ^ { 2 } + 2 } d t

Question 112

Multiple Choice

Find the derivative of the function.
g(x) =1x1t2+2dtg ( x ) = \int _ { 1 } ^ { x } \frac { 1 } { t ^ { 2 } + 2 } d t


A) 2x(x2+2) 2- \frac { 2 x } { \left( x ^ { 2 } + 2 \right) ^ { 2 } }
B) 29- \frac { 2 } { 9 }
C) 13\frac { 1 } { 3 }
D) 1x2+2\frac { 1 } { x ^ { 2 } + 2 }

Correct Answer:

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