Find an Equation of the Tangent Line to the Curve $$x = e ^ { \sqrt { t } } , \quad y = t - \ln t ^ { 6 } ; \quad t = 1$$

Short Answer

Find an equation of the tangent line to the curve at the point corresponding to the value of the parameter.
$$x = e ^ { \sqrt { t } } , \quad y = t - \ln t ^ { 6 } ; \quad t = 1$$