Find the Point(s) on the Curve Where the Tangent Is $$x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2$$

Short Answer

Find the point(s) on the curve where the tangent is horizontal.
$$x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2$$