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  2. Topic
    Mathematics
  3. Study Set
    Multivariable Calculus International
  4. Exam
    Exam 12: Vectors and the Geometry of Space
  5. Question
    Find the Point of Intersection\[L _ { 1 } : \frac { x - 17 } { 3 } = \frac { y - 58 } { 8 } = \frac { z - 23 } { 2 } , L _ { 2 } : \frac { x - 49 } { 7 } = \frac { y - 26 } { 4 } = z - 15\]
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Find the Point of Intersection

Question 115

Question 115

Short Answer

Find the point of intersection.
L1:x−173=y−588=z−232,L2:x−497=y−264=z−15L _ { 1 } : \frac { x - 17 } { 3 } = \frac { y - 58 } { 8 } = \frac { z - 23 } { 2 } , L _ { 2 } : \frac { x - 49 } { 7 } = \frac { y - 26 } { 4 } = z - 15L1​:3x−17​=8y−58​=2z−23​,L2​:7x−49​=4y−26​=z−15

Correct Answer:

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