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  2. Topic
    Mathematics
  3. Study Set
    Multivariable Calculus International
  4. Exam
    Exam 15: Multiple Integrals
  5. Question
    Find the Area of the Surface\(z = 36 - x ^ { 2 } - y ^ { 2 }\)
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Find the Area of the Surface z=36−x2−y2z = 36 - x ^ { 2 } - y ^ { 2 }z=36−x2−y2

Question 104

Question 104

Short Answer

Find the area of the surface.
The part of the surface z=36−x2−y2z = 36 - x ^ { 2 } - y ^ { 2 }z=36−x2−y2 that lies above the xyx yxy -plane.

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