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Solve the Problem t=0t = 0 , There Are 29 g29 \mathrm {~g}

Question 29

Multiple Choice

Solve the problem.
-The half-life of a certain radioactive substance is 8 years. Suppose that at time t=0t = 0 , there are 29 g29 \mathrm {~g} of the substance. Then after t years, the number of grams of the substance remaining will be:
N(t) =29(12) t/16N ( t ) = 29 \left( \frac { 1 } { 2 } \right) ^ { t / 16 }
How many grams of the substance will remain after 56 years? Round to the nearest hundredth when necessary.


A) 0.64 g0.64 \mathrm {~g}
B) 1.28 g1.28 \mathrm {~g}
C) 0.32 g0.32 \mathrm {~g}
D) 2.56 g2.56 \mathrm {~g}

Correct Answer:

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