The Acceleration Due to Gravity at or near the Surface $\frac { 1 } { 6 } g$

Short Answer

The acceleration due to gravity at or near the surface of the moon is approximately $\frac { 1 } { 6 } g$ .This is equal to: a. $0.1635 \mathrm {~m} / \mathrm { s } ^ { 2 }$
b. $981 \mathrm {~cm} / \mathrm { s } ^ { 2 }$
c. $0.57 \mathrm {~km} / \mathrm { h } ^ { 2 }$
d. $1.635 \mathrm {~m} / \mathrm { s } ^ { 2 }$
e. None of the above