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    Mathematics
  3. Study Set
    Algebra and Trigonometry Study Set 3
  4. Exam
    Exam 8: Polar Coordinates and Parametric Equations
  5. Question
    Solve the Equation in the Interval\([ 0,2 \pi )\) \(\sin x = \cos 2 x\)
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Solve the Equation in the Interval [0,2π)[ 0,2 \pi )[0,2π) sin⁡x=cos⁡2x\sin x = \cos 2 xsinx=cos2x

Question 106

Question 106

Short Answer

Solve the equation in the interval [0,2π)[ 0,2 \pi )[0,2π)
. sin⁡x=cos⁡2x\sin x = \cos 2 xsinx=cos2x

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