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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) 3tan3θ=tanθ3 \tan ^ { 3 } \theta = \tan \theta

Question 84

Short Answer

Solve the equation in the interval [0,2π)[ 0,2 \pi )
. 3tan3θ=tanθ3 \tan ^ { 3 } \theta = \tan \theta

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