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If a Ball Is Thrown Directly Upward with a Velocity y=64t−16t2y = 64 t - 16 t ^ { 2 }

Question 28

Short Answer

If a ball is thrown directly upward with a velocity of 64 ft/s, its height (in feet) after t seconds is given
by y=64t−16t2y = 64 t - 16 t ^ { 2 }
. What is the maximum height attained by the ball?

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