If a Ball Is Thrown Directly Upward with a Velocity $y = 48 t - 16 t ^ { 2 }$

Short Answer

If a ball is thrown directly upward with a velocity of 48 ft/s, its height (in feet) after t seconds is givenby $y = 48 t - 16 t ^ { 2 }$
. What is the maximum height attained by the ball?