Multiple Choice
Consider the following code snippet:
public static <T> void fun(T[] t) { ...}
Erasure by the compiler of method fun will generate which result?
A) public static void fun(Object[] t) { ...}
B) public static <T> void fun(Object[] t) { ...}
C) public static void fun(Object t) { ...}
D) public static <Object> void fun(Object t) { ...}
Correct Answer:
Verified
Correct Answer:
Verified
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