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Find the Integral Below Using an Integral Table 664x2dx\int \frac { 6 } { 64 - x ^ { 2 } } d x

Question 37

Multiple Choice

Find the integral below using an integral table. 664x2dx\int \frac { 6 } { 64 - x ^ { 2 } } d x


A) 38ln8+x8x+C\frac { 3 } { 8 } \ln \left| \frac { 8 + x } { 8 - x } \right| + C
B) 38ln64+x64x+C\frac { 3 } { 8 } \ln \left| \frac { 64 + x } { 64 - x } \right| + C  Find the integral below using an integral table.  \int \frac { 6 } { 64 - x ^ { 2 } } d x  A)   \frac { 3 } { 8 } \ln \left| \frac { 8 + x } { 8 - x } \right| + C  B)   \frac { 3 } { 8 } \ln \left| \frac { 64 + x } { 64 - x } \right| + C    C)   \frac { 3 } { 8 } \ln \left| \frac { 64 - x } { 64 + x } \right| + C  D)   \frac { 1 } { 8 } \ln \left| \frac { 8 - x } { 8 + x } \right| + C  E)   \frac { 3 } { 8 } \ln \left| \frac { 8 - x } { 8 + x } \right| + C
C) 38ln64x64+x+C\frac { 3 } { 8 } \ln \left| \frac { 64 - x } { 64 + x } \right| + C
D) 18ln8x8+x+C\frac { 1 } { 8 } \ln \left| \frac { 8 - x } { 8 + x } \right| + C
E) 38ln8x8+x+C\frac { 3 } { 8 } \ln \left| \frac { 8 - x } { 8 + x } \right| + C

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