The Probability Distribution for X Is as Follows$$\begin{array} { l | r r r r }
x & - 1 & 0 & 1 & 2 \
\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1
\end{array}$$

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The Probability Distribution for X Is as Follows$$\begin{array} { l | r r r r } 
x & - 1 & 0 & 1 & 2 \
\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1
\end{array}$$

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The Answer of The Probability Distribution for X Is as Follows$$\begin{array} { l | r r r r } 
x & - 1 & 0 & 1 & 2 \
\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1
\end{array}$$

The Probability Distribution for X Is as Follows $\begin{array} { l | r r r r } x & - 1 & 0 & 1 & 2 \\\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1\end{array}$

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The Probability Distribution for X Is as Follows x−1012p(x)0.10.250.550.1\begin{array} { l | r r r r } x & - 1 & 0 & 1 & 2 \\\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1\end{array}xp(x)​−10.1​00.25​10.55​20.1​​

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The Probability Distribution for X Is as Follows $\begin{array} { l | r r r r } x & - 1 & 0 & 1 & 2 \\\hline p ( x ) & 0.1 & 0.25 & 0.55 & 0.1\end{array}$

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