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Is the Following Bare Bones Program Self-Terminating? Explain Your Answer

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Is the following Bare Bones program self-terminating? Explain your answer.
 copy X to Z decr Z while Z not 0: decr Z decr X while X not 0:\begin{array} { l } \text { copy } \mathrm { X } \text { to } \mathrm { Z } \\\text { decr } \mathrm { Z } \\\text { while } \mathrm { Z } \text { not } 0 : \\\text { decr } \mathrm { Z } \\\text { decr } \mathrm { X } \\\text { while } \mathrm { X } \text { not } 0 :\end{array}

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No.If the program is run with ...

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