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Solve the System by the Substitution or the Addition Method {x+12=3y412x3=y1\left\{ \begin{array} { l } \frac { x + 1 } { 2 } = \frac { 3 - y } { 4 } \\\frac { - 1 - 2 x } { 3 } = \frac { y } { 1 }\end{array} \right.

Question 92

Multiple Choice

Solve the system by the substitution or the addition method.
- {x+12=3y412x3=y1\left\{ \begin{array} { l } \frac { x + 1 } { 2 } = \frac { 3 - y } { 4 } \\\frac { - 1 - 2 x } { 3 } = \frac { y } { 1 }\end{array} \right.


A) (-2, 11)
B) (1, -1)
C) (-1, -1)
D) (12,1) \left( \frac { 1 } { 2 } , 1 \right)

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