Solve the Problem $\mathrm { v } = \sqrt { 2 \mathrm { gh } },$

Multiple Choice

Solve the problem.
-A formula used to determine the velocity v in feet per second per second of an object (neglecting air resistance) after it has fallen a certain height iss v $\mathrm { v } = \sqrt { 2 \mathrm { gh } },$ , where g is the acceler where g is the acceleation due to gravity and h is the height the
Object has fallen. If the acceleration g due to gravity on Earth is approximately 32 feet per second per second,
Find the velocity of a bowling ball after it has fallen 30 feet. (Round to the nearest tenth.)

A) 31.0 ft/sec
B) 43.8 ft/sec
C) 1920 ft/sec
D) 7.7 ft/sec