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Solve the Problem x2+9x+8x and height x5x+1\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }

Question 44

Multiple Choice

Solve the problem.
-A parallelogram has areaas area x2+9x+8x and height x5x+1\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 } . Find the length of its base, by dividing its area by its height.  Solve the problem. -A parallelogram has areaas area  \frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }  . Find the length of its base, by dividing its area by its height.   A)   \frac { x + 8 } { x ^ { 4 } }  B)   x ^ { 4 } ( x + 8 )   C)   \frac { ( x + 8 )  ( x + 1 )  ^ { 2 } } { x ^ { 4 } }  D)   \frac { ( x + 8 )  ( x + 1 )  ^ { 2 } } { x ^ { 6 } }


A) x+8x4\frac { x + 8 } { x ^ { 4 } }
B) x4(x+8) x ^ { 4 } ( x + 8 )
C) (x+8) (x+1) 2x4\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 4 } }
D) (x+8) (x+1) 2x6\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 6 } }

Correct Answer:

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