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Exhibit 15-4 Consider Dissolving NaF in Water as Shown in the Equation

Question 111

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Exhibit 15-4 Consider dissolving NaF in water as shown in the equation below to answer the following question(s) :
NaF (s) + H₂ O ( Exhibit 15-4 Consider dissolving NaF in water as shown in the equation below to answer the following question(s) : NaF (s)  + H₂ O (   )    HF (aq)  + NaOH (aq)  -Refer to Exhibit 15-4. What is the base ionization constant , K b , for this reaction? K a (HF)  = 6.8 10 - 4 A)  K <sub>b</sub> = - 6.8×10<sup> - 4</sup> B)  K <sub>b</sub> = 6.8×10<sup> - 18</sup> C)  K <sub>b</sub> = 1.47×10<sup> - 11</sup> D)  K <sub>b</sub> = 1.47×10<sup> - 4</sup> E)  K <sub>b</sub> = 6.8×10<sup>10</sup> ) Exhibit 15-4 Consider dissolving NaF in water as shown in the equation below to answer the following question(s) : NaF (s)  + H₂ O (   )    HF (aq)  + NaOH (aq)  -Refer to Exhibit 15-4. What is the base ionization constant , K b , for this reaction? K a (HF)  = 6.8 10 - 4 A)  K <sub>b</sub> = - 6.8×10<sup> - 4</sup> B)  K <sub>b</sub> = 6.8×10<sup> - 18</sup> C)  K <sub>b</sub> = 1.47×10<sup> - 11</sup> D)  K <sub>b</sub> = 1.47×10<sup> - 4</sup> E)  K <sub>b</sub> = 6.8×10<sup>10</sup> HF (aq) + NaOH (aq)
-Refer to Exhibit 15-4. What is the base ionization constant , K b , for this reaction?
K a (HF) = 6.8 10 - 4


A) K b = - 6.8×10 - 4
B) K b = 6.8×10 - 18
C) K b = 1.47×10 - 11
D) K b = 1.47×10 - 4
E) K b = 6.8×1010

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