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Exhibit 16-1 Consider the Equilibrium Reaction Below to Answer the Following

Question 24

Multiple Choice

Exhibit 16-1 Consider the equilibrium reaction below to answer the following question(s) . HNO₂ + H₂ O Exhibit 16-1 Consider the equilibrium reaction below to answer the following question(s) . HNO₂ + H₂ O   H₃O + + NO₂ 1 - K a (HNO₂ )  = 4.5 10 - 4 -Refer to Exhibit 16-1. What is the concentration of nitrite ion, NO₂ - , present at equilibrium if 0.100 moles of HCl are added to 0.200 moles of HNO₂ to form one-liter of solution? A)  [NO<sub>2</sub><sup> - </sup>] = 9.00×10<sup> - 4</sup> M B)  [NO<sub>2</sub><sup> - </sup>] = 2.12×10<sup> - 3</sup> M C)  [NO<sub>2</sub><sup> - </sup>] = 9.49×10<sup> - 3</sup> M D)  [NO<sub>2</sub><sup> - </sup>] = 0.100 M E)  [NO<sub>2</sub><sup> - </sup>] = 0.200 M H₃O + + NO₂ 1 - K a (HNO₂ ) = 4.5 10 - 4
-Refer to Exhibit 16-1. What is the concentration of nitrite ion, NO₂ - , present at equilibrium if 0.100 moles of HCl are added to 0.200 moles of HNO₂ to form one-liter of solution?


A) [NO2 - ] = 9.00×10 - 4 M
B) [NO2 - ] = 2.12×10 - 3 M
C) [NO2 - ] = 9.49×10 - 3 M
D) [NO2 - ] = 0.100 M
E) [NO2 - ] = 0.200 M

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