Use Cramer S Rule to Solve the System for Z $\left\{ \begin{array} { l } x + y - z = 4 \\8 x - 6 y + 7 z = 1 \\x + 9 y - z = - 2\end{array} \right.$

Multiple Choice

Use Cramer s Rule to solve the system for z. $\left\{ \begin{array} { l } x + y - z = 4 \\8 x - 6 y + 7 z = 1 \\x + 9 y - z = - 2\end{array} \right.$

A) $z = \frac { \left| \begin{array} { c c c } 4 & 1 & - 1 \\1 & - 6 & 7 \\- 2 & 9 & - 1\end{array} \right| } { \left| \begin{array} { c c c } 1 & 1 & - 1 \\8 & - 6 & 7 \\1 & 9 & - 1\end{array} \right| }$
B) $z = \frac { \left| \begin{array} { c c c } 1 & 1 & 4 \\8 & - 6 & 1 \\1 & 9 & - 2\end{array} \right| } { \left| \begin{array} { c c c } 1 & 1 & - 1 \\8 & - 6 & 7 \\1 & 9 & - 1\end{array} \right| }$
C) $z = \frac { \left| \begin{array} { c c c } 1 & 4 & - 1 \\8 & 1 & 7 \\1 & 9 & - 2\end{array} \right| } { \left| \begin{array} { c c c } 1 & 1 & - 1 \\8 & - 6 & 7 \\1 & 9 & - 1\end{array} \right| }$
D) $z = \frac { \left| \begin{array} { c c c } 1 & 1 & - 1 \\8 & - 6 & 7 \\1 & 9 & - 1\end{array} \right| } { \left| \begin{array} { c c c } 1 & 1 & 4 \\8 & - 6 & 1 \\1 & 9 & - 2\end{array} \right| }$