The Receipts for One Showing of a Movie Were $808 $\left\{ \begin{array} { l } x + y + z = 110 \\6 x + 8 y + 7 z = 808 \\y = 2 x\end{array} \right.$

Multiple Choice

The receipts for one showing of a movie were $808 for an audience of 110 people. Children's tickets are $6, general admission is $8, and tickets for seniors are $7. Twice as many general admission tickets as children's tickets were purchased. If x is the number of children's tickets purchased, y is the number of general admissions tickets purchased, and z is the number of senior tickets purchased, write a system of three equations in three variables that models the situation.

A) $\left\{ \begin{array} { l } x + y + z = 110 \\6 x + 8 y + 7 z = 808 \\y = 2 x\end{array} \right.$
B) $\left\{ \begin{array} { l } x + y + z = 110 \\6 x + 8 y + 7 z = 808 \\x = 2 y\end{array} \right.$
C) $\left\{ \begin{array} { l } x + y + z = 808 \\6 x + 8 y + 7 z = 110 \\y = 2 x\end{array} \right.$
D) $\left\{ \begin{array} { l } x + y + z = 808 \\6 x + 8 y + 7 z = 110 \\x = 2 y\end{array} \right.$