$E _ { L I N E } = \sqrt { E _R ^ { 2 } + E _X ^ { 2 } }$

Short Answer

$E _ { L I N E } = \sqrt { E _R ^ { 2 } + E _X ^ { 2 } }$ What is the current in amperes in a 3-phase circuit when the load is 67.5 horsepower, the efficiency is 90%, the voltage is 440 volts, and the circuit power factor is 0.80? Round the answer to the nearer hundredth. $$h p = \frac { \sqrt { 3 } ( E ) ( I ) ( E f f ) ( P F ) } { 746 }$$