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A Motor Takes a Current of 8 Amps Per Leg P=3(E)(I)(PF)P = \sqrt { 3 } ( E ) ( I ) ( P F )

Question 43

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A motor takes a current of 8 amps per leg on a 440-volt, 3-phase circuit. The power factor is 0.75. What is the load in watts? Carry the answer to two decimal places. P=3(E)(I)(PF)P = \sqrt { 3 } ( E ) ( I ) ( P F )

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