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Solve Graphically 16Ω16 \Omega Their Difference Is 2Ω2 \Omega Find the Two Resistances

Question 58

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Solve graphically. The sum of two resistances is 16Ω16 \Omega . Their difference is 2Ω2 \Omega . Find the two resistances. If we let R1R _ { 1 } and R2R _ { 2 } be the two resistances, the equations are R1+R2=16R1R2=2\begin{array} { l } R _ { 1 } + R _ { 2 } = 16 \\R _ { 1 } - R _ { 2 } = 2\end{array}


A)  Solve graphically. The sum of two resistances is  16 \Omega  . Their difference is  2 \Omega  . Find the two resistances. If we let  R _ { 1 }  and  R _ { 2 }  be the two resistances, the equations are  \begin{array} { l }  R _ { 1 } + R _ { 2 } = 16 \\ R _ { 1 } - R _ { 2 } = 2 \end{array}  A)    B)    C)    D)
B)  Solve graphically. The sum of two resistances is  16 \Omega  . Their difference is  2 \Omega  . Find the two resistances. If we let  R _ { 1 }  and  R _ { 2 }  be the two resistances, the equations are  \begin{array} { l }  R _ { 1 } + R _ { 2 } = 16 \\ R _ { 1 } - R _ { 2 } = 2 \end{array}  A)    B)    C)    D)
C)  Solve graphically. The sum of two resistances is  16 \Omega  . Their difference is  2 \Omega  . Find the two resistances. If we let  R _ { 1 }  and  R _ { 2 }  be the two resistances, the equations are  \begin{array} { l }  R _ { 1 } + R _ { 2 } = 16 \\ R _ { 1 } - R _ { 2 } = 2 \end{array}  A)    B)    C)    D)
D)  Solve graphically. The sum of two resistances is  16 \Omega  . Their difference is  2 \Omega  . Find the two resistances. If we let  R _ { 1 }  and  R _ { 2 }  be the two resistances, the equations are  \begin{array} { l }  R _ { 1 } + R _ { 2 } = 16 \\ R _ { 1 } - R _ { 2 } = 2 \end{array}  A)    B)    C)    D)

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