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Solve Graphically $15 \mathrm { ft } ^ { 3 }$

Question 34

Multiple Choice

Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is $15 \mathrm { ft } ^ { 3 }$ . How much of each is in the mix if
X = the amount of concrete
Y = the amount of gravel
The equations are $\begin{array} { l } y = 4 x \\x + y = 15\end{array}$

A) $Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is 15 \mathrm { ft } ^ { 3 } . How much of each is in the mix if X = the amount of concrete Y = the amount of gravel The equations are \begin{array} { l } y = 4 x \\ x + y = 15 \end{array} A) B) C) D)$
B) $Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is 15 \mathrm { ft } ^ { 3 } . How much of each is in the mix if X = the amount of concrete Y = the amount of gravel The equations are \begin{array} { l } y = 4 x \\ x + y = 15 \end{array} A) B) C) D)$
C) $Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is 15 \mathrm { ft } ^ { 3 } . How much of each is in the mix if X = the amount of concrete Y = the amount of gravel The equations are \begin{array} { l } y = 4 x \\ x + y = 15 \end{array} A) B) C) D)$
D) $Solve graphically. In a concrete mix, there is four times as much gravel as concrete. The total volume is 15 \mathrm { ft } ^ { 3 } . How much of each is in the mix if X = the amount of concrete Y = the amount of gravel The equations are \begin{array} { l } y = 4 x \\ x + y = 15 \end{array} A) B) C) D)$

Solve Graphically 15ft315 \mathrm { ft } ^ { 3 }15ft3

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Solve Graphically $15 \mathrm { ft } ^ { 3 }$

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