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Solve Graphically $\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array}$

Question 94

Multiple Choice

Solve graphically. An electric circuit containing two currents may be expressed by the equation $\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array}$ where i ₁ and i ₂ are the currents in microamperes ( $\mu A$ ) . Find the two currents.

A) $Solve graphically. An electric circuit containing two currents may be expressed by the equation \begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\ 5 i _ { 1 } - 2 i _ { 2 } = 25 \end{array} where i 1 and i 2 are the currents in microamperes ( \mu A ) . Find the two currents. A) B) C) D)$
B) $Solve graphically. An electric circuit containing two currents may be expressed by the equation \begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\ 5 i _ { 1 } - 2 i _ { 2 } = 25 \end{array} where i 1 and i 2 are the currents in microamperes ( \mu A ) . Find the two currents. A) B) C) D)$
C) $Solve graphically. An electric circuit containing two currents may be expressed by the equation \begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\ 5 i _ { 1 } - 2 i _ { 2 } = 25 \end{array} where i 1 and i 2 are the currents in microamperes ( \mu A ) . Find the two currents. A) B) C) D)$
D) $Solve graphically. An electric circuit containing two currents may be expressed by the equation \begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\ 5 i _ { 1 } - 2 i _ { 2 } = 25 \end{array} where i 1 and i 2 are the currents in microamperes ( \mu A ) . Find the two currents. A) B) C) D)$

Solve Graphically 3i1+4i2=415i1−2i2=25\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array}3i1​+4i2​=415i1​−2i2​=25​

Multiple Choice

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Solve Graphically $\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array}$

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