If $f ( x ) = \frac { 2 } { x - 5 }$

Multiple Choice

If $f ( x ) = \frac { 2 } { x - 5 }$ find $f ( - 5 ) , f ( 0 ) , f ( 5 ) , f ( - 3 )$ .

A) $f ( - 5 ) = - \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) \text { does not exist, } f ( - 3 ) = - \frac { 1 } { 4 }$
B) $f ( - 5 ) \text { does not exist, } f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) = \frac { 1 } { 5 } , f ( - 3 ) = - \frac { 1 } { 4 }$
C) $f ( - 5 ) = \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) \text { does not exist, } f ( - 3 ) = - \frac { 1 } { 4 }$
D) $f ( - 5 ) = - \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) = \frac { 1 } { 5 } , f ( - 3 ) = \frac { 1 } { 4 }$