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Solve the System (x2y+z=135x+4y4z=52x5y+4z=13)\left(\begin{array}{llll}x&-&2 y&+&z & =&13 \\5 x&+&4 y&-&4 z & =&5 \\-2 x&-&5 y&+&4 z & =&13\end{array}\right)

Question 31

Multiple Choice

Solve the system. (x2y+z=135x+4y4z=52x5y+4z=13) \left(\begin{array}{llll}x&-&2 y&+&z & =&13 \\5 x&+&4 y&-&4 z & =&5 \\-2 x&-&5 y&+&4 z & =&13\end{array}\right)


A) x = 5, y = -3, z = 2
B) x = 3, y = -1, z = 5
C) x = 5, y = 0, z = 4
D) x = 5, y = 2, z = 5

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