Solved

The Equation Below Is in the Form h=at2+bt+ch = a t ^ { 2 } + b t + c

Question 78

Multiple Choice

The equation below is in the form h=at2+bt+ch = a t ^ { 2 } + b t + c The input is the time t, in seconds. The output is the height h of an object tossed straight up from a height c, in feet, with an initial velocity b, in feet per second. 16t2+15t+110=0- 16 t ^ { 2 } + 15 t + 110 = 0 Solve the equation for t, using the quadratic formula. Round to the nearest hundredth. Which answers are acceptable in the setting?


A) t=2.02sec, discard t=3.13t = 2.02 \mathrm { sec } \text {, discard } t = - 3.13
B) t=3.13sec, discard t=2.19t = 3.13 \mathrm { sec } , \text { discard } t = - 2.19
C) t=1.78sec, discard t=2.02t = 1.78 \mathrm { sec } , \text { discard } t = - 2.02
D) t=3.13sec, discard t=2.02t = 3.13 \mathrm { sec } , \text { discard } t = - 2.02
E) no real-number solution

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions