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Write the Standard Form of the Equation of the Hyperbola (x+3)24(y3)216/5=1\frac { ( x + 3 ) ^ { 2 } } { 4 } - \frac { ( y - 3 ) ^ { 2 } } { 16 / 5 } = 1

Question 49

Multiple Choice

Write the standard form of the equation of the hyperbola.  Write the standard form of the equation of the hyperbola.   A)   \frac { ( x + 3 )  ^ { 2 } } { 4 } - \frac { ( y - 3 )  ^ { 2 } } { 16 / 5 } = 1  B)   \frac { ( y - 3 )  ^ { 2 } } { 5 / 16 } - \frac { ( x + 3 )  ^ { 2 } } { 4 } = 1  C)   \frac { ( y - 3 )  ^ { 2 } } { 4 } - \frac { ( x + 3 )  ^ { 2 } } { 5 / 16 } = 1  D)   \frac { ( y + 3 )  ^ { 2 } } { 5 / 16 } - \frac { ( x - 3 )  ^ { 2 } } { 4 } = 1  E)   \frac { ( x - 3 )  ^ { 2 } } { 4 } - \frac { ( y + 3 )  ^ { 2 } } { 16 / 5 } = 1


A) (x+3) 24(y3) 216/5=1\frac { ( x + 3 ) ^ { 2 } } { 4 } - \frac { ( y - 3 ) ^ { 2 } } { 16 / 5 } = 1
B) (y3) 25/16(x+3) 24=1\frac { ( y - 3 ) ^ { 2 } } { 5 / 16 } - \frac { ( x + 3 ) ^ { 2 } } { 4 } = 1
C) (y3) 24(x+3) 25/16=1\frac { ( y - 3 ) ^ { 2 } } { 4 } - \frac { ( x + 3 ) ^ { 2 } } { 5 / 16 } = 1
D) (y+3) 25/16(x3) 24=1\frac { ( y + 3 ) ^ { 2 } } { 5 / 16 } - \frac { ( x - 3 ) ^ { 2 } } { 4 } = 1
E) (x3) 24(y+3) 216/5=1\frac { ( x - 3 ) ^ { 2 } } { 4 } - \frac { ( y + 3 ) ^ { 2 } } { 16 / 5 } = 1

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