The Height Y (In Feet)of a Ball That You Throw $y = - \frac { 1 } { 180 } x ^ { 2 } + x + 6$

Multiple Choice

The height y (in feet) of a ball that you throw is given by $y = - \frac { 1 } { 180 } x ^ { 2 } + x + 6$ where x is the horizontal distance (in feet) from where you release the ball. How high is the ball when it reaches its maximum height?

A) 90 feet
B) 51 feet
C) 102 feet
D) 6 feet
E) 70 feet