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Find the Probability of the Event with Odds Against It P(E)=9991,000P ( E ) = \frac { 999 } { 1,000 }

Question 62

Multiple Choice

Find the probability of the event with odds against it 1,000 to 1.


A) P(E) =9991,000P ( E ) = \frac { 999 } { 1,000 }
B) P(E) =11,000P ( E ) = \frac { 1 } { 1,000 }
C) P(E) =9991,001P ( E ) = \frac { 999 } { 1,001 }
D) P(E) =1,0001,001P( E ) = \frac { 1,000 } { 1,001 }
E) P(E) =11,001P ( E ) = \frac { 1 } { 1,001 }

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