Multiple Choice
In the photoelectron spectrum of carbon disulfide, CS2, ionization from the highest occupied, 1g, molecular orbital results in little vibrational structure. In contrast, ionization from the next lowest occupied 1u molecular orbital results in a long vibrational progression in the 1 symmetric stretching mode of the CS2+ ion. Which of the following descriptions of the bonding in neutral CS2 best explains these observations?
A) Both the 1g and 1u molecular orbitals of CS2 are non-bonding in character.
B) The 1g molecular orbital of CS2 is antibonding in character and the 1u orbital is non-bonding in character.
C) The 1g molecular orbital of CS2 is nonbonding in character and the 1u orbital is bonding in character.
D) Both the 1g and 1u molecular orbitals of CS2 are antibonding in character.
Correct Answer:

Verified
Correct Answer:
Verified
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