Solved

The Area of the Surface Generated by Revolving the Curve x(t)=43cost,x ( t ) = 4 - 3 \cos t,

Question 7

Multiple Choice

The area of the surface generated by revolving the curve with x(t) =43cost,x ( t ) = 4 - 3 \cos t, about the x-axis is


A) πln(π+44) \pi \ln \left( \frac { \pi + 4 } { 4 } \right)
B) 6πln(π24) 6 \pi \ln \left( \frac { \pi - 2 } { 4 } \right)
C) 6πln(π+24) 6 \pi \ln \left( \frac { \pi + 2 } { 4 } \right)
D) 6πln(π+22) 6 \pi \ln \left( \frac { \pi + 2 } { 2 } \right)
E) 6πln(π22) 6 \pi \ln \left( \frac { \pi - 2 } { 2 } \right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions